0=c^2+10c+16

Solution for 0=c^2+10c+16 equation:

0=c^2+10c+16

We move all terms to the left:

0-(c^2+10c+16)=0

We add all the numbers together, and all the variables

-(c^2+10c+16)=0

We get rid of parentheses

-c^2-10c-16=0

We add all the numbers together, and all the variables

-1c^2-10c-16=0

a = -1; b = -10; c = -16;
Δ = b2-4ac
Δ = -102-4·(-1)·(-16)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-6}{2*-1}=\frac{4}{-2}
=-2
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+6}{2*-1}=\frac{16}{-2}
=-8
$